My turn, my turn. Here are my big cutie heads.
eta - have fixed the access. I will switch it back to friends only in a bit since it is pics of the kids - but it is public for now.
You're nice, and you're funny and you don't smoke, and okay, werewolf, but that's not all the time. I mean, three days out of the month, I'm not much fun to be around, either.
Willow ,'Get It Done'
Spike's Bitches 27: I'm Embarrassed for Our Kind.
[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.
SuziQ - Oct 31, 2005 5:35:46 pm PST #1857 of 10003
Back tattoos of the mother is that you are absolutely right - Ame
brenda m - Oct 31, 2005 5:39:10 pm PST #1858 of 10003
If you're going through hell/keep on going/don't slow down/keep your fear from showing/you might be gone/'fore the devil even knows you're there
Taunter!
(IOW, getting a 403, you don't have permission page)
askye - Oct 31, 2005 5:49:34 pm PST #1859 of 10003
Thrive to spite them
Everyone's babies (big and little) are so cute!
I'm going to stagger over to my bed and keel over from a massive lethal cuteness overload.
Emily - Oct 31, 2005 5:55:21 pm PST #1860 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Hil, that sounds awful. Do you have a medical advice place you can call? My insurance used to have a 24-hour nurse line, for medical questions where you didn't think you needed to go to the emergency room, but weren't sure.
Er, and I have a math question, but I feel like maybe you should be resting your eye.
Ahem. And now that I thought to look, apparently that was an hour ago. Oh well.
SailAweigh - Oct 31, 2005 6:05:27 pm PST #1861 of 10003
Nana korobi, ya oki. (Fall down seven times, stand up eight.) ~Yuzuru Hanyu/Japanese proverb
K-Bug looks really, really dead, there. Hope she scared lots of people! CJ is just too cute for words. You make pretty (big) babies, Maidengurl.
Cashmere - Oct 31, 2005 6:09:24 pm PST #1862 of 10003
Now tagless for your comfort.
Skippity Skim...my sister's dial up SUCKS! It sucks for viewing pictures, dammit!
Owen is the boy you want Em to marry, but Leif is the boy she ends up bringing home.
I love Gud.
Halloween pictures will be uploaded when we return home tomorrow night. Then there will be catching up. Maybe.
Hil R. - Oct 31, 2005 6:10:34 pm PST #1863 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l
Emily, I do have a medical advice line, but I lost the number. My eye is feeling a bit better now -- still sort of a "something isn't right here" feeling, but not really hurting anymore.
What's your math question?
Emily - Oct 31, 2005 6:18:22 pm PST #1864 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
If G and G' are finite groups, and there's a homomorphism from G to G', I need to show that the cardinality of the image of G is a divisor of the cardinality of G. My thinking (about the case where it's not one-to-one or trivial) so far has been this: there's an equivalence relation, where a and b in G are in the same cell if they map to the same element of G', and then (and here's the fuzzy part) you can pick one representative of each cell in such a way that they make up a subgroup H which has the same cardinality as the image of G. And then... er, I thought I had something which came next relating |H| to |G|, but now I'm not sure. In any case, am I even on the right track?
Hil R. - Oct 31, 2005 6:20:58 pm PST #1865 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l
Hmm. I'm not sure, but that does seem like it's probably the right track.
Emily - Oct 31, 2005 6:26:28 pm PST #1866 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Well, does the cardinality of a finite subgroup have to be the divisor of the cardinality of the finite group it's in, or is that only for cyclic groups?
I have this sneaking suspicion that the answer should have something to do with cosets, but honestly, my brain's not taking to cosets very well.