If you want me to leave, you can put your hands on my hot, tight little body and make me.

Spike ,'Get It Done'


Spike's Bitches 27: I'm Embarrassed for Our Kind.  

[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.


Hil R. - Oct 31, 2005 6:10:34 pm PST #1863 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

Emily, I do have a medical advice line, but I lost the number. My eye is feeling a bit better now -- still sort of a "something isn't right here" feeling, but not really hurting anymore.

What's your math question?


Emily - Oct 31, 2005 6:18:22 pm PST #1864 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

If G and G' are finite groups, and there's a homomorphism from G to G', I need to show that the cardinality of the image of G is a divisor of the cardinality of G. My thinking (about the case where it's not one-to-one or trivial) so far has been this: there's an equivalence relation, where a and b in G are in the same cell if they map to the same element of G', and then (and here's the fuzzy part) you can pick one representative of each cell in such a way that they make up a subgroup H which has the same cardinality as the image of G. And then... er, I thought I had something which came next relating |H| to |G|, but now I'm not sure. In any case, am I even on the right track?


Hil R. - Oct 31, 2005 6:20:58 pm PST #1865 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

Hmm. I'm not sure, but that does seem like it's probably the right track.


Emily - Oct 31, 2005 6:26:28 pm PST #1866 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

Well, does the cardinality of a finite subgroup have to be the divisor of the cardinality of the finite group it's in, or is that only for cyclic groups?

I have this sneaking suspicion that the answer should have something to do with cosets, but honestly, my brain's not taking to cosets very well.


meara - Oct 31, 2005 6:26:52 pm PST #1867 of 10003

Hil, probably the contact was too dry, and it tried to take your eyeball with it. Y'know, or something. If it still feels bad tomorrow, after you have your eyes closed for sleeping a decent amount (assuming/hoping you're sleeping a decent amount), then you probably want to do something about it...

My friend came over and talked to me while I cleaned, and put clothes on hangers, and in the hour she was here, I got more done than I have in WEEKS. See? I just need someone to come guilt/entertain me. Otherwise I end up on the internet...


Hil R. - Oct 31, 2005 6:29:08 pm PST #1868 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

Well, does the cardinality of a finite subgroup have to be the divisor of the cardinality of the finite group it's in,

Yes. At least, I'm almost positive it does. It's been awhile since I've really looked at algebra, but I'm just about certain that's true.


P.M. Marc - Oct 31, 2005 6:30:19 pm PST #1869 of 10003
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear

Lillian pictures up: [link]


DavidS - Oct 31, 2005 6:32:34 pm PST #1870 of 10003
"Look, son, if it's good enough for Shirley Bassey, it's good enough for you."

Back from trick or treating. Best. Halloween. Ever.

Mainly because Emmett was totally committed to his Harpo performance, never broke character when he whistled "thank you" and gurned on command. He was an especial hit with grandpas who declared things like, "Harpo! You get EXTRA candy!"


P.M. Marc - Oct 31, 2005 6:32:40 pm PST #1871 of 10003
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear

Cutiebel!

Love the kitty costume. Everyone has such cute kids!

Ellie looks so wary in her peapod. And a certain young lady looks just beautiful in her black dress. Then we have Em, FEAR HER EVIL PINK CUTENESS!


dw - Oct 31, 2005 6:32:42 pm PST #1872 of 10003
Silence means security silence means approval

Annabel approves of the Lilybean.

Me: Annabel, there's Lillian.

Annabel: (pointing to the screen) Hi!