Hmm. I'm not sure, but that does seem like it's probably the right track.
Simon: I, uh... I never-never shot anyone before. Book: I was there, son. I'm fair sure you haven't shot anyone yet.
'War Stories'
Spike's Bitches 27: I'm Embarrassed for Our Kind.
[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.
Hil R. - Oct 31, 2005 6:20:58 pm PST #1865 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l
Emily - Oct 31, 2005 6:26:28 pm PST #1866 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Well, does the cardinality of a finite subgroup have to be the divisor of the cardinality of the finite group it's in, or is that only for cyclic groups?
I have this sneaking suspicion that the answer should have something to do with cosets, but honestly, my brain's not taking to cosets very well.
meara - Oct 31, 2005 6:26:52 pm PST #1867 of 10003
Hil, probably the contact was too dry, and it tried to take your eyeball with it. Y'know, or something. If it still feels bad tomorrow, after you have your eyes closed for sleeping a decent amount (assuming/hoping you're sleeping a decent amount), then you probably want to do something about it...
My friend came over and talked to me while I cleaned, and put clothes on hangers, and in the hour she was here, I got more done than I have in WEEKS. See? I just need someone to come guilt/entertain me. Otherwise I end up on the internet...
Hil R. - Oct 31, 2005 6:29:08 pm PST #1868 of 10003
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l
Well, does the cardinality of a finite subgroup have to be the divisor of the cardinality of the finite group it's in,
Yes. At least, I'm almost positive it does. It's been awhile since I've really looked at algebra, but I'm just about certain that's true.
P.M. Marc - Oct 31, 2005 6:30:19 pm PST #1869 of 10003
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear
Lillian pictures up: [link]
DavidS - Oct 31, 2005 6:32:34 pm PST #1870 of 10003
"Look, son, if it's good enough for Shirley Bassey, it's good enough for you."
Back from trick or treating. Best. Halloween. Ever.
Mainly because Emmett was totally committed to his Harpo performance, never broke character when he whistled "thank you" and gurned on command. He was an especial hit with grandpas who declared things like, "Harpo! You get EXTRA candy!"
P.M. Marc - Oct 31, 2005 6:32:40 pm PST #1871 of 10003
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear
Cutiebel!
Love the kitty costume. Everyone has such cute kids!
Ellie looks so wary in her peapod. And a certain young lady looks just beautiful in her black dress. Then we have Em, FEAR HER EVIL PINK CUTENESS!
dw - Oct 31, 2005 6:32:42 pm PST #1872 of 10003
Silence means security silence means approval
Annabel approves of the Lilybean.
Me: Annabel, there's Lillian.
Annabel: (pointing to the screen) Hi!
Emily - Oct 31, 2005 6:32:49 pm PST #1873 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Yes. At least, I'm almost positive it does. It's been awhile since I've really looked at algebra, but I'm just about certain that's true.
All right. Well, I'll put what I have, and he'll likely give me some credit for it, anyway. It's not even that big a deal (especially since I didn't hand in a whole chapter's worth of homework), but I don't like to leave it blank. Thank you! Also, good luck with the eye. Sounds like you probably just irritated it a bunch.
P.M. Marc - Oct 31, 2005 6:34:23 pm PST #1874 of 10003
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear
Hee!
It's amazing how grown up Annabel looks in those. I think it's the tall lean thing that does it.