Er, more math, sorry.
The function f is differentiable on the interval 0 < x < 4. If f(1)=1 and f(3)=7, then for some 1 < c < 3, f'(c) must be equal to:
1, 2, 3, 4, or 6?
I thought I had an answer but was wrong. Anybody?
ETA: Also, 99? Just a cool number.
I want to send a link of that FAQ to all the boys I know and say, "This is how to do it."
I'd really rather not get beaten up repeatedly, thank you very much.
not only does a watched pot never boil, a watched inbox never receives mail.
Just so you all know, I'm doing math to put off figuring out how to get a count of our faculty as of a date in the past. I'm not sure my brain's sufficiently present.
I thought I had an answer but was wrong. Anybody?
My best guess would be f(c) = 4, assuming c = 2, but it's just a guess.
Can you imagine the power of an infinite number of Theremins, bringing down defenses, shattering eardrums.
Somehow "piercing" and "woo-woo-woo" don't quite go together in my mind.
The function f is differentiable on the interval 0 < x < 4. If f(1)=1 and f(3)=7, then for some 1 < c < 3, f'(c) must be equal to:
1, 2, 3, 4, or 6?
3. It's the mean value theorem: for some value on the interval, the slope must be equal to the average slope, which is (7-1)/(3-1) = 3.
Jon, that is just about the sweetest story ever. Even with the Tex Avery moments, just so damn sweet. Millions of congratulations all over again!