The count of three isn't a plan. It's Sesame Street.

Buffy ,'First Date'


What Happens in Natter 35 Stays in Natter 35  

Off-topic discussion. Wanna talk about corsets, duct tape, or physics? This is the place. Detailed discussion of any current-season TV must be whitefonted.


§ ita § - May 14, 2005 7:40:35 am PDT #4154 of 10001
Well not canonically, no, but this is transformative fiction.

Yup. I think so.

Then I have no idea how changing your pick affects your chances of winning. How does knowing that card affect anything? If I'd known it was a goat before I picked my card, my choices would be 50/50. If I find out afterwards, the odds shift?


Betsy HP - May 14, 2005 7:41:16 am PDT #4155 of 10001
If I only had a brain...

That's why it's a paradox.


Hil R. - May 14, 2005 7:42:00 am PDT #4156 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

I have a question about the Make A Deal problem -- does the host turn over a goat card (forget for the moment that I want a goat, and already have a car) whether or not I've picked the car?

Yes. Otherwise, you'd then know that the one you picked wasn't it, and he'd have just ruled out one of the other other two, leaving you knowing that the remaining one was it.


§ ita § - May 14, 2005 7:42:32 am PDT #4157 of 10001
Well not canonically, no, but this is transformative fiction.

It wasn't presented as a paradox, though. Just a problem whose solution runs counter to much intuition.


Hil R. - May 14, 2005 7:45:51 am PDT #4158 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

When you pick yours the first time, you've got a 1/3 chance of being right. Him telling you that one of the other two isn't the car gives you no new information about the one you picked to begin with -- you already knew that at least one of those other two wasn't a car. You've still got a 1/3 chance of being right with the one you picked. But that leaves a 2/3 chance of being wrong, and that 2/3 chance is now entirely on the still hidden unpicked one.

(I really can't figure out a good way to explain this entirely. The way I was able to totally convince myself was just to set up all the different possible situations and look at the results.)


§ ita § - May 14, 2005 7:48:07 am PDT #4159 of 10001
Well not canonically, no, but this is transformative fiction.

If you can't explain it to me, Hil, I don't feel so bad about not getting it.


Hil R. - May 14, 2005 7:51:03 am PDT #4160 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

Let's say that the car is in door 1. If you picked door 1, then you'll get it if you stay. If you picked door 2 or door 3, then you'll get the car if you switch. There's a 1/3 chance you picked right on that first try, but a 2/3 chance you picked wrong, so in 1/3 of the cases you'll get the car if you stay, but in 2/3 you'll get it if you switch.


Stephanie - May 14, 2005 7:53:58 am PDT #4161 of 10001
Trust my rage

I'm glad others are confused because I din't get it last night.


§ ita § - May 14, 2005 7:56:04 am PDT #4162 of 10001
Well not canonically, no, but this is transformative fiction.

What's at the core of the problem? Being given the chance to switch to a card that has a 1/2 chance of being the right one? I mean, 1/2 if you started from step 2?

You know, this might be one I just accept, or run the numbers on. My big issue is that I want there to be some calculation that gets you from the odds on the first pass to the new odds, and I just can't see it.


Hil R. - May 14, 2005 8:00:33 am PDT #4163 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

What's at the core of the problem? Being given the chance to switch to a card that has a 1/2 chance of being the right one? I mean, 1/2 if you started from step 2?

I think the core of the problem is that the odds don't change. You've got a 1/3 chance of being right, 2/3 chance of being wrong. Suppose they don't tell you "door 2 is not a car." They just say, "You can stay where you are, or you can switch to doors 2 and 3. If either of those is a car, you get it; if neither of them is, you don't." That's an equivalent problem -- knowing which door of 2 and 3 is the one without a car doesn't change anything.