Happy Birthday to Iris!
{{Bitches}}
Sorry your mom is giving you a hard time, Hil. In our family it is the opposite. We give my mom a hard time about not getting proper medical care. And she lies about it!! My sister went to her house to mail her some stuff she left in NY and found medication she had purchased for mom that she never opened and totally lied about taking. Grrr.
Math is making my brain hurt. I am trying to help Brendon with Trig, but we can't get past the preliminary stuff because I can't remember, or find explanation for, the simple stuff. Help! We have simplified the very complex equation down to x² - 2x = 3 in about 20 steps, which we can see with the eyeballs means that x=3, but there is a mathy way to get there for an in between step (or 10) and I can't figure it out. Wah!
Yes, on the list is finding a math tutor because it has been 20 years since we did this stuff and we fail as parents in assisting at this point.
I missed ChiKat's birthday! I hope it was a wonderful day.
Laura, make that into x^2 - 2x - 3 = 0, and then factor the left side to get (x-3)(x+1)=0, so x=3 or x=-1.
Oh, happy belated birthday, ChiKat!
{Hil}
Thanks, Hil, but still confused. I can see how you factored it, but I don't see how that gets closer to the answer of x=3. Is it just that at some point it is ok to just see that 3 works? I'd type the whole original problem, but that would make me crazy on a keyboard. We were at the x² - 2x = 3 point of simplifying when he jumped to x=3. Is that a reasonable jump?
Also, worship your mathy brain.
You can jump to x=3 and x=-1 when you get it factored into the linear factors. Once you have (x-3)(x+1)=0, you know that either x-3=0 or x+1=0 (since if the product of two things is 0, then one of the factors must be 0), and so then solve those for x=3 or x=-1.
Oh, the practice test is on line. The original problem is No.1 here [link]
Ah! I understand that. Now I can explain it to him. Thanks.
