I missed ChiKat's birthday! I hope it was a wonderful day.
Spike's Bitches 43: Who am I kidding? I love to brag.
[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risqué (and frisqué), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.
Laura, make that into x^2 - 2x - 3 = 0, and then factor the left side to get (x-3)(x+1)=0, so x=3 or x=-1.
Oh, happy belated birthday, ChiKat!
{Hil}
Happy Birthday to Iris!
Thanks, Hil, but still confused. I can see how you factored it, but I don't see how that gets closer to the answer of x=3. Is it just that at some point it is ok to just see that 3 works? I'd type the whole original problem, but that would make me crazy on a keyboard. We were at the x² - 2x = 3 point of simplifying when he jumped to x=3. Is that a reasonable jump?
Also, worship your mathy brain.
You can jump to x=3 and x=-1 when you get it factored into the linear factors. Once you have (x-3)(x+1)=0, you know that either x-3=0 or x+1=0 (since if the product of two things is 0, then one of the factors must be 0), and so then solve those for x=3 or x=-1.
Oh, the practice test is on line. The original problem is No.1 here [link]
Ah! I understand that. Now I can explain it to him. Thanks.
I flunked Geometry.
I'm okay with that.
I only took Algebra and Geometry then took business type math in college. Statistics and Quantitative methods. DH took Calculus and Trigonometry in college and tutored, but 20 years of not thinking about it leaves him just as clueless as me. At least I do enjoy the process of learning it so I can help him. But seriously, math hard.