But that's just my point! You she obeys! She obeys you! There's obeying going on right under my nose!

Wash ,'War Stories'


Spike's Bitches 24: I'm Very Seldom Naughty.  

[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.


Emily - Jun 06, 2005 12:39:26 pm PDT #2964 of 10001
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

And what about transitive? Is that a=b implies a+c=b+c?

ETA: Of course I could google it. But I like talking to you people!


-t - Jun 06, 2005 12:42:26 pm PDT #2965 of 10001
I am a woman of various inclinations and only some of the time are they to burn everything down in frustration

Transitive is a=b and b=c -> a=c (or with < or > replacing the =s)

Hil is very clever. All I can think of when I see "commutative principle" is "What's purple and commutes?"

Ans: An Abelian grape

And that may well summarize What I Learned in Abstract Algebra.


Tom Scola - Jun 06, 2005 12:43:42 pm PDT #2966 of 10001
Remember that the frontier of the Rebellion is everywhere. And even the smallest act of insurrection pushes our lines forward.

Equality is transitive because a = b and b = c implies that a = c.


Emily - Jun 06, 2005 12:51:49 pm PDT #2967 of 10001
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

Okay, that's what I thought. So then what property is involved in the proof that a+z = b+z => a=b?


Strix - Jun 06, 2005 12:53:09 pm PDT #2968 of 10001
A dress should be tight enough to show you're a woman but loose enough to flee from zombies. — Ginger

Ignoring the disturbing math talk, to say g'night. I'll be back tomorrow morning!


Gris - Jun 06, 2005 12:54:35 pm PDT #2969 of 10001
Hey. New board.

So then what property is involved in the proof that a+z = b+z => a=b?

Quite.


Hil R. - Jun 06, 2005 12:55:30 pm PDT #2970 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

So then what property is involved in the proof that a+z = b+z => a=b?

I think that's the inverse property, since what you're doing there is adding the inverse of z to each side.


Emily - Jun 06, 2005 12:58:17 pm PDT #2971 of 10001
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

G'night, Erin!

Looking again at the question, I think they were looking for associative, for the step from (a+z)+-z=(b+z)+-z to a+(z+-z)=b+(z+-z). Interesting. I wouldn't have thought to make that two steps, but I guess it makes sense.

Anyway, thank you.


Aims - Jun 06, 2005 12:59:13 pm PDT #2972 of 10001
Shit's all sorts of different now.

Dear Person,

If you can't help me with what I asked for, please call me and let me know. The reason I came to you, instead of my usual contact, was becuse I needed an answer today. If I wanted an answer tomorrow, I would have waited for my contact to get back in.

Dickhead.

Ta, Aimee, Your Neighborhood A/R Girl


Atropa - Jun 06, 2005 1:24:41 pm PDT #2973 of 10001
The artist formerly associated with cupcakes.

Workweek Bunny Update:

Apparently the bunnies don't appear until after 3PM. I didn't see any until I was halfway done with my walk, and then I saw two. The work day I go for a walk and not see any bunnies will be a letdown.