Liese - It looks like -L is a flag for openSSH. I don't know if it's available in other implementations of SSH. I'd suggest one of two solutions: (1) install openSSH, or (2) use the PuTTY "option B".

Great, Jon, thanks. I can install openSSH, which is probably what I should have gone with in the first place.

I'm having an Instagram problem: when I try to take a picture it sends me to settings to enable access to my camera - but there is no spot in settings where I can enable access to my camera.

Anyone know what to do?

What kind of phone, sumi?

If an iPhone its under privacy, then camera--there should be a list of apps that have requested access and you can turn that access on or off.

So here's my progress: openSSH totally worked, so I got it installed on the NAS, port forwarding working, everything talking. Only I can't actually log onto the Crashplan software to control it over there, because apparently I still don't have internet connectivity from the Drobo. Which makes sense, because I couldn't get the email notifications up and running either, but had just deferred that problem to deal with later.

I'm thinking maybe I have my default gateway, etc. set up incorrectly. That is to say, I have everything set up as zeros, because I thought that set of routing was all about the LAN, not about getting to the internet. If I change the settings to what my modem uses, then I can't access the drobo through the LAN at all. So I am at another impasse.

I realized that what I needed to do with my iphone is update the IOS. (Finally)

I'm trying to figure out how much of the chemical energy in methane (CH4) is due to the carbon atom and how much due to 4 hydrogen atoms. (I'm looking at process to make methane out of hydrogen. Because there are good reasons why hydrogen gas is far less usable for certain purposes than methane (natural gas) I'm trying to figure out how much more energy is in the methane than in the carbon alone. According to my handing chemical table of elements the energy of ionization for hydrogen 131 kJ/mole whereas the the same figure for carbon is 153. So if "energy of ionization" is what I'm looking for, then the methane molecule has 4.4 time the energy that if the carbon atom was just used in a coal substitute. But am I figuring this right? Is "energy of ionization" really what I'm looking for?

Hmm. I am not as up on my chemistry as I once was, but I think that your approach doesn't really work because it doesn't look at the actual combustion reaction itself. You need to compare the energy change of burning methane vs. the energy of burning pure hydrogen gas or pure carbon gas. I think. The issue is that plenty of energy will be locked on the products in either case, so it is the energy released by the process that is actually interesting.

I don't really remember how to do that though.

This might help: [link]