How's your adorable fam?
We are great. Em turns a year in a week and a half. She's just had her first taste of (very very very) diluted apple juice and seems to love it. Joe loves his job and I'm...well, it pays me. I'm looking for other more satidfying work that doesn't involve garter belts and dollar bills.
Um, what do you do for a living, again, Aim?
er - next week - I KNOW!!!
The sad thing is that I am bound to miss it.
Santorum
I'm the only person on this planet who thinks "Santorum" looks like "Suntory."
For relaxing times... make it Santorum time.
Woot! Just got back from seeing a performance by the touring Broadway company of Twyla Tharp's Moving Out. The dancers were great, particularly the one who played Eddie. I was disappointed at first when I found out it was a night that the second string pianist was playing, but as it turned out he was SO bad they replaced him with with headliner Darren Holden at intermission. I think I may like Holden's take on some of the songs better than Billy Joel's.
I KNOW!!!
They look so pretty. I will be taping. That last scene between Abby and Luka... I think I've lived that. Not with Goran, sadly, but still...
Here's the question:
In a lottery in which the ratio of losing tickets to the number of winning tickets is 39:1, how many tickets should one buy to give oneself even odds of winning a prize?
At first I thought this was one of those "How many rolls of the dice before there's an even chance of getting a 6" questions, but it's not multiple trials, just one. Shouldn't the answer be... uh. 20?
20 sounds correct to me. Each ticket has one chance in forty to win, so to make the odds even, you'd need twenty chances at it.
A better analogy than dice would be a roulette wheel without the 0 and 00 holes.