Yay MG and MGDH!
Buffy. When I saw you stop the world from, you know, ending, I just assumed that was a big week for you. Turns out I suddenly find myself needing to know the plural of 'apocalypse.'
Riley ,'Potential'
Spike's Bitches 27: I'm Embarrassed for Our Kind.
[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.
Gudanov - Dec 13, 2005 6:04:27 am PST #9531 of 10003
Coding and Sleeping
sumi - Dec 13, 2005 6:04:36 am PST #9532 of 10003
Art Crawl!!!
Woo hoo! MG!
vw bug - Dec 13, 2005 6:05:03 am PST #9533 of 10003
Mostly lurking...
That's wonderful news, Suzi! Yay!!!!!
Topic!Cindy - Dec 13, 2005 6:05:13 am PST #9534 of 10003
What is even happening?
Okay. Assume that I am a moron. What is a good, VERY SIMPLE book that would give me an introduction to binary code and how it works?
Whatever for? You did catch that Turing's already dead, right?
Topic!Cindy - Dec 13, 2005 6:05:43 am PST #9535 of 10003
What is even happening?
Yay, Suzi and DH!!!
Deena - Dec 13, 2005 6:06:10 am PST #9536 of 10003
How are you me? You need to stop that. Only I can be me. ~Kara
YAY Suzi! Money in the house and a DH out of it! Man, that's a double header.
Steph L. - Dec 13, 2005 6:06:38 am PST #9537 of 10003
Unusually and exceedingly peculiar and altogether quite impossible to describe
What do you mean by binary code? Just, converting numbers from base 10 to binary and back
Um. Well. I guess so?
I don't know what you mean by binary code.
Er. I don't know how else to describe it. The whole 0-1 dealio.
SuziQ - Dec 13, 2005 6:06:57 am PST #9538 of 10003
Back tattoos of the mother is that you are absolutely right - Ame
Thanks all. I'm not officially releasing the ~ma until he starts, cause there was that one job where he lasted less than 6 hours...but still...this appears to be a good one.
Emily - Dec 13, 2005 6:08:55 am PST #9539 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Hil: why is a^p = a in Z sub p when p is prime? Also, if you divide f(x) by (x-a), why is the remainder always f(a)? It's sort of obvious why this is true for f(a)=0, but even when it isn't it's true, and I'm racking my brain as to why.
Steph, I don't know how much detail you need. There's lots of web sites, e.g. [link]
And of course I pretty much champ at the bit to explain anything mathy.
beth b - Dec 13, 2005 6:09:16 am PST #9540 of 10003
oh joy! Oh Rapture ! I have a brain!
yay for mg's dh!