Don't suppose there's a Hil around for me to heartlessly exploit for her spicy math brains?
I've got two questions left for tomorrow, and NO CLUE.
Yeah, I could do that, but I'm paralyzed with not caring very much.
Spike ,'Showtime'
Spike's Bitches 27: I'm Embarrassed for Our Kind.
[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.
Emily - Nov 07, 2005 2:50:23 pm PST #3343 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Gris - Nov 07, 2005 2:54:10 pm PST #3344 of 10003
Hey. New board.
Emily, I can probably help. Or make Gershwin Girl do it. Both of us know algebra.
SuziQ - Nov 07, 2005 2:54:13 pm PST #3345 of 10003
Back tattoos of the mother is that you are absolutely right - Ame
Brownie sundaes are served.
Waaaaaaaaa. I haven't had dinner yet and am still chugging on this darned paper.
Amy - Nov 07, 2005 2:56:41 pm PST #3346 of 10003
Because books.
Brownie sundaes sound very tempting right now.
The best part of today is no crippling pain!
That's wonderful! And I hope they get their acts together with scheduling.
Jen - Nov 07, 2005 2:59:07 pm PST #3347 of 10003
love's a dream you enter though I shake and shake and shake you
Ewan McGregor in makeup!
Ewan McGregor looks a lot like Eddie Izzard in that picture.
Cashmere - Nov 07, 2005 3:02:48 pm PST #3348 of 10003
Now tagless for your comfort.
Survived work today, and I seem to have found the person to talk to if I want anything accomplished. I spoke to one of them about the fact that they are overscheduling me, and she immediately spoke to all of the managers, who all feigned ignorance (which is complete bullshit). She promised me that it won't happen again. We'll see... The best part of today is no crippling pain! Some minor, annoying pain, but that is manageable.
This sounds much better, sj. Go you for taking the issue to someone that can do something about it. I hope the situation keeps improving.
Mmmm...brownies...mmm...sundaes....*drool*
Emily - Nov 07, 2005 3:05:06 pm PST #3349 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
Yay! Okay, here are my two remaining issues:
If a finite group has only one subgroup of a particular order, how do I know that subgroup is normal? Also, I need a group which has no elements of finite order greater than one, but which has a factor group with all finite elements. Any takers?
(Not that I think any subgroup is abnormal. I would never want to put that kind of pressure on a subgroup, which after all is constantly living in the shadow of the Big G, which is having its own issues about the lingering possibility of being called simple.)
Trudy Booth - Nov 07, 2005 3:13:46 pm PST #3350 of 10003
Greece's financial crisis threatens to take down all of Western civilization - a civilization they themselves founded. A rather tragic irony - which is something they also invented. - Jon Stewart
The nice thing about comfort food is that it's actually comforting.
Chow down, ladies.
Gris - Nov 07, 2005 3:18:23 pm PST #3351 of 10003
Hey. New board.
Okay. For the first one, you have a subgoup N of G that is of order k. Take g in G and n in N such that g^-1*n*g is not in N. Then the group defined by g^-1*n2* g for each n2 in N will be a group of order k (I'm 97% sure - showing it is your job) that isn't N, a nice contradiction.
For the second one, um, I dunno. I'd guess there's some way to show that (Z, +) works, but I'm not sure. Sorry, I'm not so great with this stuff.
Emily - Nov 07, 2005 3:32:50 pm PST #3352 of 10003
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola
I was heading in that direction, but hadn't quite managed to make it into a subgroup of its own. Thank you! Now the second one... rrrrgh. Part of the problem is that I keep getting messed up by the word element -- I understand an element of G, but is an element of the factor group G/H a coset? So that would translate to finding an infinite group with a finite subgroup -- I can do that, I think, but I want to make sure what's being measured here.