It's like, in the middle of all this, I'm paranoid that you'll think I don't like poetry.

Buffy ,'Empty Places'


Spike's Bitches 26: Damn right I'm impure!  

[NAFDA] Spike-centric discussion. Lusty, lewd (only occasionally crude), risque (and frisque), bawdy (Oh, lawdy!), flirty ('cuz we're purty), raunchy talk inside. Caveat lector.


Topic!Cindy - Oct 10, 2005 4:46:56 pm PDT #7651 of 10001
What is even happening?

Cindy, I liked the pun.

Thank you. Of course, it was a limerick, but we knew that. We were just testing those others.


Polter-Cow - Oct 10, 2005 4:47:20 pm PDT #7652 of 10001
What else besides ramen can you scoop? YOU CAN SCOOP THIS WORLD FROM DARKNESS!

Also, my pun got no love, and now I'm worried that it wasn't clear what the "stinks" was in reference to, and that I've offended everyone. It was supposed to be P-C saying it stinks that he missed the swag.

I got it! Although at first, I read it as Pete saying that.


Emily - Oct 10, 2005 4:48:40 pm PDT #7653 of 10001
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

Hmm. I guess what I was saying is essentially the same as (123) and (23), in that (123) composed with (23) gives (132), but (23) composed with (123) gives, er... (213).

(Which looks enticingly like an area code, but I don't know for where. 212 I would know, but that's not a valid permutation. Mind you, 617 is, proving once again its supremacy! Go Sox!)


Hil R. - Oct 10, 2005 4:52:11 pm PDT #7654 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

Tell me if this makes any sense: Dn must be a subset of Sn (right?). Then there's some permutation (reflection or diagonal flip) such that vertex x goes to itself, but all the other vertices change, and also some premutation (rotation) such that all vertices change by 1. Then I can show these don't commute. Would that suffice?

The thing about all vertices but one changing would only work if n is odd. If you're doing it that way, then you'd probably have to do two cases, one for even n and one for odd n.

So I get that I can find a noncommuting pair for any particular set, but how do I go about proving the claim for all n > 2?

The way I was going about it was finding the smallest group which would be a subgroup of any Sn with n greater than 2, i.e. S3, then showing that that's nonabelian, and therefore any group that contains it is nonabelian.


Anne W. - Oct 10, 2005 4:53:17 pm PDT #7655 of 10001
The lost sheep grow teeth, forsake their lambs, and lie with the lions.

All the above just goes to prove that you never know what kind of conversation you're going to wander into around here.


Cass - Oct 10, 2005 4:57:44 pm PDT #7656 of 10001
Bob's learned to live with tragedy, but he knows that this tragedy is one that won't ever leave him or get better.

she was in the middle of telling me she may have cancer
Oh hell, Emily. I'll cross my fingers on the cat scratch??? And maybe some math~ma because it sounds funny in my head.
You file for unemployment online in California. It's pretty easy.
Oh good. My nap has made me just feel edgy and cranky, so good news is basically good right now. And I think I have a headache from crying earlier. Clotted cream seems like it would help.

they are perky because they are not large enough to be used shelfishly.
Don't be shelfish! Share with the rest of the 'fistas...


Trudy Booth - Oct 10, 2005 5:02:49 pm PDT #7657 of 10001
Greece's financial crisis threatens to take down all of Western civilization - a civilization they themselves founded. A rather tragic irony - which is something they also invented. - Jon Stewart

t rubs cass' temples


Emily - Oct 10, 2005 5:07:46 pm PDT #7658 of 10001
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

and therefore any group that contains it is nonabelian.

Oh, duh. Didn't occur to me. But I could use mine with the clause (or leaves x and y unchanged if n is even), right? It doesn't really change the proof -- if I'm doing it by using the isomorphism with a regular n-gon, then there's always a permutation where x goes to x but x+1 goes to something else, right? because x and y would have to be opposite each other.

Anyway, I'm tired and have done pretty well in the class so far, so I think it's okay if I'm a bit sketchy on this homework, so long as I go look up the answers if I get them wrong.


P.M. Marc - Oct 10, 2005 5:16:59 pm PDT #7659 of 10001
So come, my friends, be not afraid/We are so lightly here/It is in love that we are made; In love we disappear

Gronk.

We failed to contact the Kindercare people today. I kept forgetting it was Monday, on account of Paul being home.

However, we made a dozen cinnamon rolls, had my parents over for gingerbread pancakes with pears and lemon butter, took Paul's grandmother to the Apple store to pick up a Mini (OMG, G5 20" iBook LUST), and I'm curling up with the girl while Paul starts making the soup from the stock I made last night (when I also dried a couple of apples in prep for our future fruitcake).

Freaking productive on the domestic front, at least. Our only break today has been the hour or so we took to watch an episode of Due South. I want a Vecchio of my very own.


Hil R. - Oct 10, 2005 5:17:27 pm PDT #7660 of 10001
Sometimes I think I might just move up to Vermont, open a bookstore or a vegan restaurant. Adam Schlesinger, z''l

But I could use mine with the clause (or leaves x and y unchanged if n is even), right? It doesn't really change the proof -- if I'm doing it by using the isomorphism with a regular n-gon, then there's always a permutation where x goes to x but x+1 goes to something else, right? because x and y would have to be opposite each other.

Sounds good.