Gabriel: Are you trying to destroy this family? Simon: I didn't realize it would be so easy.

'Safe'


Natter .38 Special  

Off-topic discussion. Wanna talk about corsets, duct tape, or physics? This is the place. Detailed discussion of any current-season TV must be whitefonted.


le nubian - Sep 22, 2005 7:08:44 am PDT #9923 of 10002
"And to be clear, I am the hell. And the high water."

You know, I had heard about Clooney. This sounds really wild. More links:

[link]

[link]


§ ita § - Sep 22, 2005 7:12:07 am PDT #9924 of 10002
Well not canonically, no, but this is transformative fiction.

Woobie!

Despite pain so intense he could barely walk, the 44-year-old actor-director still appeared on the red carpet at the 'Ocean's Twelve' premiere last December, although he was too weak to climb three stairs up to "The Insider"'s own platform.

Or, you know, he just wanted to go home to his pig.


le nubian - Sep 22, 2005 7:13:01 am PDT #9925 of 10002
"And to be clear, I am the hell. And the high water."

If spinal fluid is leaking through your fucking nose, I guess you would be in pain.

Damn.


Nilly - Sep 22, 2005 7:13:19 am PDT #9926 of 10002
Swouncing

Greek style

Emily, your proof looks completely OK to the entirely-not-a-mathematician me, who has no idea what is that Greek style and what other styles exist or anything of that sort.

What are the Hebrew initials and what are the words they stand for?

M.Sh.L. (we have the one letter that stands for the "sh" sound). It's pronounced usually "mashal", which is also a word in Hebrew, meaning a proverb, a fable, or an allegory. They are the initials of "ma shehaya lehokhiakh". "ma" = what, "shehaya" - that was and "lehokhiakh" - to be proven.

which I already knew and used to use as a sort of meditation to get to sleep oh god am I geeky enough yet?

My brother used to calculate all sorts of roots and powers in order to pass the time when he had to stang guard on his army service.


juliana - Sep 22, 2005 7:14:31 am PDT #9927 of 10002
I’d be lying if I didn’t say that I miss them all tonight…

Poor Clooney! I hereby volunteer to comfort and cosset him, because I'm a giver like that.


Emily - Sep 22, 2005 7:17:10 am PDT #9928 of 10002
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

who has no idea what is that Greek style and what other styles exist or anything of that sort.

Oh, it's just that the Greeks didn't have the notation to do the proof this way, so their proof has to do with comparing two lines of different length, subtracting one from the other and the remainder of that one from the first one, and the remainder of that from the remainder above, and so on in order to prove that there was, basically, no common divisor. Only they said it much more complicatedly.


Nilly - Sep 22, 2005 7:20:15 am PDT #9929 of 10002
Swouncing

so their proof has to do with comparing two lines of different length

So they did their algebra through some sort of a geometric language, you mean?


msbelle - Sep 22, 2005 7:38:31 am PDT #9930 of 10002
I remember the crazy days. 500 posts an hour. Nubmer! Natgbsb

mmmm Clooney.

back to work.


tommyrot - Sep 22, 2005 7:53:06 am PDT #9931 of 10002
Sir, it's not an offence to let your cat eat your bacon. Okay? And we don't arrest cats, I'm very sorry.

OK, appointment had been made for this afternoon at a really good optometrist. So I get to avoid Jilli-pokeage.


Emily - Sep 22, 2005 7:56:22 am PDT #9932 of 10002
"In the equation E = mc⬧, c⬧ is a pretty big honking number." - Scola

Well, they didn't really have algebra, is the thing. They had "number" -- which meant positive integers -- and "magnitude" -- which was lines and shapes and things you could measure by hand -- and the two probably overlapped but were certainly not the same thing. So the square root of two wasn't actually a number, but it was a magnitude, and it was proved incommensurable (irrational) by performing operations with other lines.

I think. I'm still trying to wrap my brain around it all, while also trying to keep up with "If a straight line is cut into equal and unequal segments, the rectangle contained by the unequal segments of the whole together with the square on the straight line between the points of seccion is equal to the square on the half."