Only 6 more HBPs to break the record: Plunk Biggio*
My best guess here was that someone was doing some kind of pledge where people would throw copies of the upcoming Harry Potter book at him.
Okay, -t, so let's say we've got a graph of airplane velocity. From time 0 to time 0.5 (hours) it goes directly up from 100 to 600 mph. From 0.5 to 3.5 it does 600 mph. From 3.5 to 4.5 it goes directly down from 600 to 100 again. What's the total distance it travels, and how do you go about getting it?
Yes, this should be easy. Apparently, however, I got it all wrong.
BF and I are starting TV-less Tuesday tonight. We decided we were spending too much time watching TV and/or videos--we go out once or twice a week to movies as it is. Cinema is awesome and all, but reading and taking walks and stuff like that was getting lost in the shuffle. Looking forward to it--even though tonight's planned highlight is "wash the dog."
ETA--hooray for EM having a job and better financials for Hec and Gamine!JZ!
Do you have a DVR, Robin?
What's the total distance it travels, and how do you go about getting it?
You could integrate the first and third parts, and add them to 3 x 600 to get the total distance. But I'm pretty sure there's a way not involving integration....
eta: I think it's OK to take the average speed for each of the first and third parts to calculate the distance for each.
But my brain is a little sluggish today....
Yes, this should be easy. Apparently, however, I got it all wrong.
Well, you're starting from a false premise. Aircraft start at 0 mph, not 100. Or it it's the take off speed, most planes that can do 600 mph need to be going a bit faster than 100 to get off the ground in the first place. :)
We have TiVo (and worship it like unto a God), but what with The Daily Show and Baseball games and various movies, things pile up.
BF and I are starting TV-less Tuesday tonight.
I interpret your choice of day thusly: "Dammit, if Buffy's not on Tuesday night, then fuck Tuesday altogether!"
Wait!
Katefate is here!
I haven't seen her in ages!
Hi Katefate!
(this post brought to you by the exclaimation point!)
Yes, this should be easy. Apparently, however, I got it all wrong.
Actually for the problem as written, if you take the average speed of the plane while it's accelerating or decelerating times the time it accelerates or decelerates, and add that the distance traveled while it's cruising, you should get the answer they're looking for.
Or what tommy said.
