So, let's say I had a right triangle, with angles of 60 and 30 degrees, and the side between the right angle and the 30 degree angle has a length of 4. How long is the side between the right angle and the 60-degree angle? Please show your work.

4/sqrt(3). A 30/60/90 triangle is half an equilateral triangle, so the shorter side is equal to half the length of the hypotenuse.

Late, as usual...

I was left with a craving for goldfish for the rest of the day

Old School Black Supermodels... beverly? iman?

Rupaul?

Alibelle, I'm on campus MWF. It's best to catch me in the afternoons, after 2.

Rupaul?

snerk!

Sorry -- just curious. I got nothing.

It's okay.

But! You could apply to be a personal assistant to a cranky almost-star and tell us stories.

Now there's an idea. I would be sure to write them down, so I'd remember all the best ones. And I'd send you all some green m&m's, or something.

Alibelle, have you tried the placement folks at school?

Yeah. I have to go back, but they are not as helpful as they could be. Basically, their advice is internships and signing up at monster.com, but sign up specifically through USC and work the alumni network. Which I'm down with, and all.

And LJ is just telling me "Our."

aha! And here I thought it was a problem with our crappy webfiltering.

Websense makes me tear my hair. Especially when it times out after you've opened an email to send or started replying to a post on LJ. And then it won't reload and won't send or make the post. Really damned annoying.

Happy Friday, Natterinos!

> In fact, if you wander around the USC campus yelling the names of old school black supermodels, her sister may answer and you can get it all from the horse's mouth.

Yes, gather around your auntie ita as she speaks the legends of USC.

Rupaul?

bahahahaha...

10 points for Robin! As ever, I t heart Robin.

They should just memorize it.

Well, they're trying. But the point isn't the memorization of those (they actually had the proportions to consult) but that they be able to figure out how to apply it given new measurements.

Okay, the equilateral thing? Makes total sense. Didn't occur to me at the time (because I don't think I ever memorized, or possibly was ever taught, these special triangles), but that would be helpful. And also, using x^2 + 4^2 = (2x)^2 would be easier for them, I think, than sqrt(3)x = 4.

It's academic, since the unit is over, but I'm trying to figure out how I should have handled it. Thank you!